WebDec 1, 2024 · 3 to convert url to string use this var myurl: NSURL var urlString: String = myurl.absoluteString hope it helps Share Improve this answer Follow answered Dec 3, 2024 at 12:05 Wassim Ben Hssen 509 6 22 I have to modify to urlString = (strurl as AnyObject).absoluteString! – Antonio Abrantes Dec 6, 2024 at 1:20 Add a comment 3 WebMar 28, 2024 · Use the String method addingPercentEncoding (withAllowedCharacters:) to URL encode a string directly: var decoded = "url components" var encoded = decoded.addingPercentEncoding( withAllowedCharacters: .urlQueryAllowed ) // encoded is "url%20components" URL Property Examples URLs and Strings
swift - Cannot convert Double to String - Stack Overflow
WebAnd I try to convert Data to String in this line: returnData = String (data: dataVar, encoding: .utf8) Swift compiler gives me an error, and change this line to returnData = String (data: dataVar, encoding: .utf8)! , when I execute this line I get empty returnData variable. If I use basic example line print (String (data: data, encoding: .utf8 ... WebSep 29, 2014 · The reason why you can't do that is because String doesn't have an initializer accepting a double or a float, whereas it implements initializers for all integer types (Int, Uint, Int32, etc.). So @derdida's solution is the right way to do it. I discourage using the description property. portmarnock hotel and golf links green fees
how to convert url to string in ios/swift? - Stack Overflow
WebMay 3, 2024 · results in error: cannot convert value of type 'String' to expected argument type 'Character' I also tried creating a character variable var selectedChar:Character = selectedLetter but I get a conversion error: error: cannot convert value of type 'String?' to specified type 'Character' WebIn Swift 3, the answer appears to have changed. Now, you want to use the String initializer init (describing:) Or, to use the code from the question: result = single_result.valueForKey ("Level") let resultString = String (describing: result) Note that usually you don't want valueForKey. That is a KVO method that will only work on NSObjects. WebJan 28, 2024 · Cannot convert value of type 'String' to expected argument type 'URLSession' Ask Question Asked 4 years, 2 months ago Modified 4 years, 2 months ago Viewed 2k times 0 I use Alamofire 4.0, Swift 4.2 and Xcode 10.2 to request Http Api I have url constant: let weatherUrl = "http://api.openweathermap.org/data/2.5/weather" And … portmarnock hotel and golf links dublin